Finite Math Examples

$f (x) = 5 x^{2} + 2 x - 7$

Step 1

Find the x-intercepts.

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Step 1.1

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = 5 x^{2} + 2 x - 7$

Step 1.2

Solve the equation.

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Step 1.2.1

Rewrite the equation as $5 x^{2} + 2 x - 7 = 0$ .

$5 x^{2} + 2 x - 7 = 0$

Step 1.2.2

Factor by grouping.

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Step 1.2.2.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 5 \cdot - 7 = - 35$ and whose sum is $b = 2$ .

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Step 1.2.2.1.1

Factor $2$ out of $2 x$ .

$5 x^{2} + 2 (x) - 7 = 0$

Step 1.2.2.1.2

Rewrite $2$ as $- 5$ plus $7$

$5 x^{2} + (- 5 + 7) x - 7 = 0$

Step 1.2.2.1.3

Apply the distributive property.

$5 x^{2} - 5 x + 7 x - 7 = 0$

Step 1.2.2.2

Factor out the greatest common factor from each group.

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Step 1.2.2.2.1

Group the first two terms and the last two terms.

$(5 x^{2} - 5 x) + 7 x - 7 = 0$

Step 1.2.2.2.2

Factor out the greatest common factor (GCF) from each group.

$5 x (x - 1) + 7 (x - 1) = 0$

Step 1.2.2.3

Factor the polynomial by factoring out the greatest common factor, $x - 1$ .

$(x - 1) (5 x + 7) = 0$

Step 1.2.3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 1 = 0$

$5 x + 7 = 0$

Step 1.2.4

Set $x - 1$ equal to $0$ and solve for $x$ .

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Step 1.2.4.1

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Step 1.2.4.2

Add $1$ to both sides of the equation.

$x = 1$

Step 1.2.5

Set $5 x + 7$ equal to $0$ and solve for $x$ .

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Step 1.2.5.1

Set $5 x + 7$ equal to $0$ .

$5 x + 7 = 0$

Step 1.2.5.2

Solve $5 x + 7 = 0$ for $x$ .

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Step 1.2.5.2.1

Subtract $7$ from both sides of the equation.

$5 x = - 7$

Step 1.2.5.2.2

Divide each term in $5 x = - 7$ by $5$ and simplify.

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Step 1.2.5.2.2.1

Divide each term in $5 x = - 7$ by $5$ .

$\frac{5 x}{5} = \frac{- 7}{5}$

Step 1.2.5.2.2.2

Simplify the left side.

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Step 1.2.5.2.2.2.1

Cancel the common factor of $5$ .

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Step 1.2.5.2.2.2.1.1

Cancel the common factor.

$\frac{5 x}{5} = \frac{- 7}{5}$

Step 1.2.5.2.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 7}{5}$

Step 1.2.5.2.2.3

Simplify the right side.

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Step 1.2.5.2.2.3.1

Move the negative in front of the fraction.

$x = - \frac{7}{5}$

Step 1.2.6

The final solution is all the values that make $(x - 1) (5 x + 7) = 0$ true.

$x = 1, - \frac{7}{5}$

Step 1.3

x-intercept(s) in point form.

x-intercept(s): $(1, 0), (- \frac{7}{5}, 0)$

Step 2

Find the y-intercepts.

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Step 2.1

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = 5 {(0)}^{2} + 2 (0) - 7$

Step 2.2

Solve the equation.

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Step 2.2.1

Remove parentheses.

$y = 5 \cdot 0^{2} + 2 (0) - 7$

Step 2.2.2

Remove parentheses.

$y = 5 {(0)}^{2} + 2 (0) - 7$

Step 2.2.3

Simplify $5 {(0)}^{2} + 2 (0) - 7$ .

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Step 2.2.3.1

Simplify each term.

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Step 2.2.3.1.1

Raising $0$ to any positive power yields $0$ .

$y = 5 \cdot 0 + 2 (0) - 7$

Step 2.2.3.1.2

Multiply $5$ by $0$ .

$y = 0 + 2 (0) - 7$

Step 2.2.3.1.3

Multiply $2$ by $0$ .

$y = 0 + 0 - 7$

Step 2.2.3.2

Simplify by adding and subtracting.

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Step 2.2.3.2.1

Add $0$ and $0$ .

$y = 0 - 7$

Step 2.2.3.2.2

Subtract $7$ from $0$ .

$y = - 7$

Step 2.3

y-intercept(s) in point form.

y-intercept(s): $(0, - 7)$

Step 3

List the intersections.

x-intercept(s): $(1, 0), (- \frac{7}{5}, 0)$

y-intercept(s): $(0, - 7)$

Step 4